Global Analytic Functions On Real Analytic Manifolds: A Proof
Let's dive into the fascinating question of how we can prove the existence of global analytic functions on real analytic manifolds. This is a cornerstone concept in understanding the behavior of functions on these spaces. We'll explore the intricacies of real analytic manifolds, cotangents, and the conditions under which a global analytic function can be guaranteed to exist.
Understanding Real Analytic Manifolds
To really get our heads around this, let's start by defining what we mean by a real analytic manifold. Guys, a real analytic manifold, denoted as , is essentially a manifold equipped with a real analytic structure. This means that around each point on the manifold, we can find a coordinate chart where the transition maps between overlapping charts are real analytic functions. In simpler terms, this means that the functions describing how we move between different coordinate systems are not just smooth (infinitely differentiable) but also can be represented by convergent power series.
Now, why is this important? Well, the real analytic nature of the manifold gives us a powerful tool: the ability to use power series to represent functions locally. This is crucial because analytic functions have very strong properties. For instance, if two analytic functions agree on a small open set, they must agree everywhere on their connected domain. This rigidity is what allows us to extend local properties to global ones, under suitable conditions.
Consider a simple example: the real line . We can cover it with a single coordinate chart (the identity map), and clearly, the transition map is just the identity, which is analytic. So, is a real analytic manifold. Similarly, any open subset of can be given a real analytic structure in a straightforward manner. More generally, if we have a manifold and we can find an atlas (a collection of charts) such that all transition maps are real analytic, then we've equipped our manifold with a real analytic structure.
Real analytic structures are quite rigid. For example, a complex manifold always has an underlying real analytic structure because holomorphic functions (complex analytic functions) have real and imaginary parts that are real analytic. However, not every smooth manifold admits a real analytic structure, and the study of which manifolds do admit such structures is a deep and interesting area of research.
The Role of Cotangents
Next, let's talk about cotangents. At a point on our manifold , the cotangent space, denoted as , is the vector space of all linear functionals on the tangent space . In simpler terms, it's the space of all ways to assign a real number to each tangent vector at in a linear fashion. A cotangent at is simply an element of this cotangent space. We can think of it as a linear functional that acts on tangent vectors at the point .
The cotangent space is dual to the tangent space. This means that if you have a basis for the tangent space, you can find a corresponding dual basis for the cotangent space. If we have local coordinates around , then the differentials form a basis for the cotangent space at . Any cotangent can then be written as a linear combination of these differentials: , where the coefficients are real numbers.
The concept of cotangents is crucial when we're dealing with differentials of functions. The differential of a function at a point , denoted as , is a cotangent at . It tells us how the function changes infinitesimally in different directions at the point . Specifically, if is a tangent vector at , then gives the rate of change of in the direction of .
So, when we say that we want to find a global analytic function such that , we're essentially saying that we want to find a function whose rate of change at the point matches the cotangent . This is a very specific condition, and it's not always possible to find such a function. The existence of such a depends on the properties of the manifold and the cotangent .
Proving the Existence of a Global Analytic Function
Now, let's address the main question: How can we prove that there exists a global analytic function such that ? This is where things get interesting, folks! The existence of such a function is not guaranteed for all manifolds and cotangents. It often depends on certain topological and geometric properties of the manifold.
One approach to proving the existence of such a function involves constructing it locally and then extending it globally. Here’s a possible strategy:
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Local Existence: First, we need to show that there exists a local analytic function defined in a neighborhood of such that . This can often be done using the local coordinates around . If are local coordinates and , then we can define in a small neighborhood of . This function is clearly analytic, and its differential at is equal to .
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Analytic Continuation: The next step is to extend this local function to a global analytic function. This is where the real challenge lies. Analytic continuation is a powerful technique, but it doesn't always work. It involves extending the domain of an analytic function while preserving its analyticity. If we can find a path from any point in to , we can try to extend the function along this path. However, the result might depend on the path chosen, leading to multiple values of the function at the same point. This is known as monodromy.
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Conditions for Global Existence: To ensure the existence of a global analytic function, we need to impose conditions that prevent monodromy. One such condition is that the manifold is simply connected. A simply connected manifold is one where every closed loop can be continuously deformed to a point. In this case, the analytic continuation along any path from to will give the same value, ensuring that the function is well-defined globally.
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De Rham Cohomology: Another approach involves using de Rham cohomology. If the first de Rham cohomology group of is trivial (i.e., ), then every closed 1-form is exact. In our case, if we can show that the 1-form corresponding to is closed, then it must be exact, meaning that there exists a function such that everywhere on . This condition is closely related to the topological properties of .
Example and Counterexamples
Let's consider a simple example. Suppose , which is simply connected and has trivial de Rham cohomology. Then, for any cotangent at any point , we can always find a global analytic function such that . This is because we can simply define , where is a point in and is the vector from to .
However, if (the circle), things are different. The circle is not simply connected, and its first de Rham cohomology group is non-trivial. In this case, it is not always possible to find a global analytic function such that for an arbitrary cotangent . For example, if corresponds to a non-zero constant multiple of around the circle, then there is no global function that satisfies this condition.
Conclusion
In conclusion, proving the existence of a global analytic function such that on a real analytic manifold is a complex problem that depends heavily on the topological and geometric properties of the manifold. Techniques such as local existence, analytic continuation, simple connectedness, and de Rham cohomology play crucial roles in determining whether such a function exists. Hopefully, this discussion has shed some light on this fascinating area of mathematics!